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X(X+23)-10X+3X^2=0
We add all the numbers together, and all the variables
3X^2-10X+X(X+23)=0
We multiply parentheses
3X^2+X^2-10X+23X=0
We add all the numbers together, and all the variables
4X^2+13X=0
a = 4; b = 13; c = 0;
Δ = b2-4ac
Δ = 132-4·4·0
Δ = 169
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{169}=13$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(13)-13}{2*4}=\frac{-26}{8} =-3+1/4 $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(13)+13}{2*4}=\frac{0}{8} =0 $
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